(2y^2-10y)/(25y-5y^2)

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Solution for (2y^2-10y)/(25y-5y^2) equation: 


D( y )

25*y-(5*y^2) = 0

25*y-(5*y^2) = 0

25*y-(5*y^2) = 0

25*y-5*y^2 = 0

25*y-5*y^2 = 0

DELTA = 25^2-(-5*0*4)

DELTA = 625

DELTA > 0

y = (625^(1/2)-25)/(-5*2) or y = (-625^(1/2)-25)/(-5*2)

y = 0 or y = 5

y in (-oo:0) U (0:5) U (5:+oo)

(2*y^2-(10*y))/(25*y-(5*y^2)) = 0

(2*y^2-10*y)/(25*y-5*y^2) = 0

2*y^2-10*y = 0

2*y*(y-5) = 0

y-5 = 0 // + 5

y = 5

2*y*(y-5) = 0

25*y-5*y^2 = 0

5*y*(5-y) = 0

5-y = 0 // - 5

-y = -5 // * -1

y = 5

5*y*(y-5) = 0

(2*y*(y-5))/(5*y*(y-5)) = 0

( 2*y )

2*y = 0 // : 2

y = 0

( y-5 )

y-5 = 0 // + 5

y = 5

y in { 0} 

y in { 5} 

y belongs to the empty set

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